Mastering $-8ax^2 - 16ax + 10a$: A Step-by-Step Guide

by Viktoria Ivanova 54 views

Hey guys! Let's dive into this intriguing mathematical expression: โˆ’8ax2โˆ’16ax+10a-8ax^2 - 16ax + 10a. At first glance, it might seem a bit intimidating, but don't worry, we'll break it down step by step and uncover its hidden secrets. We're going to explore different ways to simplify, analyze, and understand this expression. Think of it as a mathematical adventure where we're the explorers, and the expression is our mysterious treasure map. We'll use various techniques like factoring, finding roots, and analyzing its graphical representation to fully grasp what this expression is all about. So, buckle up, grab your mathematical tools, and let's embark on this journey together!

Factoring: The Key to Simplification

Our primary goal here is to simplify the expression, and the best way to do that is by factoring. Factoring is like reverse engineering; we're trying to find the smaller building blocks that, when multiplied together, give us our original expression. In this case, we notice that all the terms have a common factor. Can you spot it? That's right, it's 2a. Let's pull that out:

โˆ’8ax2โˆ’16ax+10a=2a(โˆ’4x2โˆ’8x+5)-8ax^2 - 16ax + 10a = 2a(-4x^2 - 8x + 5)

Now, we have a simpler expression inside the parentheses: โˆ’4x2โˆ’8x+5-4x^2 - 8x + 5. This is a quadratic expression, and we can try to factor it further. Factoring a quadratic can sometimes be tricky, but with a bit of practice, you'll become a pro. The idea is to find two binomials (expressions with two terms) that, when multiplied, give us the quadratic. There are several techniques for factoring quadratics, such as trial and error, the quadratic formula, or completing the square. For this particular quadratic, let's try factoring by grouping. This involves finding two numbers that add up to the coefficient of the x term (-8) and multiply to the product of the coefficient of the x^2 term (-4) and the constant term (5), which is -20.

So, we need two numbers that add up to -8 and multiply to -20. After a bit of thought, we can see that -10 and 2 fit the bill. Now, we can rewrite the middle term (-8x) using these two numbers:

โˆ’4x2โˆ’8x+5=โˆ’4x2โˆ’10x+2x+5-4x^2 - 8x + 5 = -4x^2 - 10x + 2x + 5

Next, we group the terms in pairs and factor out the greatest common factor (GCF) from each pair:

(โˆ’4x2โˆ’10x)+(2x+5)=โˆ’2x(2x+5)+1(2x+5)(-4x^2 - 10x) + (2x + 5) = -2x(2x + 5) + 1(2x + 5)

Notice that we now have a common binomial factor: (2x+5)(2x + 5). We can factor this out:

โˆ’2x(2x+5)+1(2x+5)=(2x+5)(โˆ’2x+1)-2x(2x + 5) + 1(2x + 5) = (2x + 5)(-2x + 1)

Putting it all together, the factored form of the original expression is:

โˆ’8ax2โˆ’16ax+10a=2a(2x+5)(โˆ’2x+1)-8ax^2 - 16ax + 10a = 2a(2x + 5)(-2x + 1)

Key Takeaway: Factoring helps us break down complex expressions into simpler components, making them easier to analyze and work with. It's like dismantling a machine to understand how each part contributes to the whole.

Finding the Roots: Where the Expression Equals Zero

Now that we've factored the expression, let's find its roots. The roots of an expression are the values of x that make the expression equal to zero. Finding the roots is crucial because they tell us where the graph of the expression intersects the x-axis. They're also important in solving equations and inequalities involving the expression.

To find the roots, we set the factored expression equal to zero:

2a(2x+5)(โˆ’2x+1)=02a(2x + 5)(-2x + 1) = 0

For this product to be zero, at least one of the factors must be zero. So, we have three possibilities:

  1. 2a=02a = 0
  2. 2x+5=02x + 5 = 0
  3. โˆ’2x+1=0-2x + 1 = 0

The first possibility, 2a=02a = 0, implies that a=0a = 0. However, this would make the entire expression zero, which isn't very interesting for our analysis. So, we'll focus on the other two possibilities.

Let's solve 2x+5=02x + 5 = 0 for x:

2x=โˆ’52x = -5

x=โˆ’52x = -\frac{5}{2}

So, one root is x = - rac{5}{2} or -2.5.

Now, let's solve โˆ’2x+1=0-2x + 1 = 0 for x:

โˆ’2x=โˆ’1-2x = -1

x=12x = \frac{1}{2}

So, the other root is x=12x = \frac{1}{2} or 0.5.

Key Takeaway: The roots of an expression are the x-values where the expression equals zero. They provide valuable information about the expression's behavior and its graph. In this case, we found two roots: -2.5 and 0.5, which means the graph of the expression will intersect the x-axis at these points.

Analyzing the Graph: Visualizing the Expression

To truly understand this expression, let's visualize its graph. The expression โˆ’8ax2โˆ’16ax+10a-8ax^2 - 16ax + 10a represents a quadratic function, which means its graph is a parabola. A parabola is a U-shaped curve, and its orientation (whether it opens upwards or downwards) and its shape depend on the coefficients in the quadratic expression. The roots we found earlier tell us where the parabola intersects the x-axis.

The general form of a quadratic function is f(x)=ax2+bx+cf(x) = ax^2 + bx + c. In our case, we have f(x)=โˆ’8ax2โˆ’16ax+10af(x) = -8ax^2 - 16ax + 10a. The coefficient of the x2x^2 term, which is -8a, determines the parabola's orientation. If -8a is positive, the parabola opens upwards, and if it's negative, the parabola opens downwards. This is a crucial point, so let's make it bold: The sign of the coefficient of the x^2 term determines the parabola's orientation.

The vertex of the parabola is its highest or lowest point, depending on its orientation. The x-coordinate of the vertex can be found using the formula:

xvertex=โˆ’b2ax_{vertex} = -\frac{b}{2a}

In our case, a=โˆ’8aa = -8a and b=โˆ’16ab = -16a, so:

xvertex=โˆ’โˆ’16a2(โˆ’8a)=โˆ’โˆ’16aโˆ’16a=โˆ’1x_{vertex} = -\frac{-16a}{2(-8a)} = -\frac{-16a}{-16a} = -1

To find the y-coordinate of the vertex, we plug this x-value back into the original expression:

yvertex=โˆ’8a(โˆ’1)2โˆ’16a(โˆ’1)+10a=โˆ’8a+16a+10a=18ay_{vertex} = -8a(-1)^2 - 16a(-1) + 10a = -8a + 16a + 10a = 18a

So, the vertex of the parabola is at the point (-1, 18a). This tells us a lot about the shape and position of the parabola. If a is positive, the vertex is above the x-axis, and if a is negative, the vertex is below the x-axis.

Now, let's consider the overall shape of the parabola. Since the coefficient of the x2x^2 term is -8a, if a is positive, the parabola opens downwards, and if a is negative, the parabola opens upwards. This means that the sign of a has a significant impact on the graph's appearance. Let's make this point strong:

The sign of a determines the parabola's concavity (whether it opens upwards or downwards).

We also know the roots of the expression are -2.5 and 0.5. These are the points where the parabola intersects the x-axis. Combining this information with the vertex and the orientation, we can sketch a rough graph of the parabola. For example, if a is positive, the parabola opens downwards, has a vertex at (-1, 18a) (which is above the x-axis), and intersects the x-axis at -2.5 and 0.5. This gives us a clear picture of the expression's behavior.

Key Takeaway: Visualizing the graph of the expression helps us understand its behavior. The parabola's orientation, vertex, and roots provide valuable insights into its properties.

Impact of 'a': A Parameter's Influence

The parameter a in the expression โˆ’8ax2โˆ’16ax+10a-8ax^2 - 16ax + 10a plays a crucial role in determining the expression's behavior. As we've seen, the sign of a affects the parabola's orientation, and its value affects the vertex's position. This means that changing a can dramatically alter the graph of the expression.

If a is positive, the parabola opens downwards, and the vertex is above the x-axis. As a increases, the parabola becomes steeper, and the vertex moves further away from the x-axis. If a is negative, the parabola opens upwards, and the vertex is below the x-axis. As the absolute value of a increases, the parabola again becomes steeper, and the vertex moves further away from the x-axis.

The roots of the expression also depend on a. However, we found the roots by setting the factored expression equal to zero: 2a(2x+5)(โˆ’2x+1)=02a(2x + 5)(-2x + 1) = 0. The roots are determined by the factors (2x+5)(2x + 5) and (โˆ’2x+1)(-2x + 1), which do not involve a. This means that the roots remain the same regardless of the value of a. This is an important observation, so let's highlight it in italics:

The roots of the expression remain constant regardless of the value of a.

Understanding the impact of parameters like a is fundamental in mathematics. It allows us to generalize our understanding of expressions and predict their behavior under different conditions. In this case, we've seen how a affects the shape and position of the parabola while leaving the roots unchanged.

Key Takeaway: Parameters in mathematical expressions have a significant impact on their behavior. Understanding these impacts allows us to generalize our knowledge and predict how expressions will change under different conditions. Analyzing the impact of the parameter a helps us understand the behavior of the equation across different scenarios.

Conclusion: Mastering the Expression

Wow, guys, we've come a long way! We started with a seemingly complex expression, โˆ’8ax2โˆ’16ax+10a-8ax^2 - 16ax + 10a, and we've successfully factored it, found its roots, analyzed its graph, and understood the impact of the parameter a. We've seen how factoring simplifies the expression, how roots tell us where the graph intersects the x-axis, how the graph provides a visual representation of the expression's behavior, and how parameters like a influence the overall shape and position of the graph. Itโ€™s pretty cool how all these concepts work together, right?

By breaking down the expression step by step and using different mathematical tools, we've gained a deep understanding of its properties. This is the essence of mathematical exploration: taking something complex and unraveling its mysteries. Remember, every mathematical expression has a story to tell, and it's our job as mathematicians to listen and interpret that story. So, keep exploring, keep questioning, and keep pushing the boundaries of your mathematical knowledge!