Parabola Equation: Find Equation From Minimum Point

by Viktoria Ivanova 52 views

Hey there, math enthusiasts! Ever stumbled upon a parabola problem that just made you scratch your head? Well, you're not alone. Parabolas, with their elegant curves and quirky equations, can sometimes feel like a puzzle. But don't worry, we're here to break it down and make it crystal clear. Let's dive into a classic parabola problem that involves identifying the correct equation given its minimum point. So, grab your thinking caps, and let's get started!

The Parabola Puzzle: Understanding the Vertex Form

Okay, guys, let's kick things off by understanding the question at hand. We've got a parabola, and we know it has a minimum point at (-3, 9). This is super important because it tells us a lot about the parabola's shape and position. Now, the question asks us to identify which equation could represent this function. To crack this, we need to understand the vertex form of a parabola's equation. The vertex form is like the secret code to understanding parabolas, and it's written as:

f(x)=a(xβˆ’h)2+kf(x) = a(x - h)^2 + k

Where:

  • (h, k) is the vertex of the parabola (the minimum or maximum point).
  • a determines whether the parabola opens upwards (if a > 0) or downwards (if a < 0) and how stretched or compressed it is.

The Beauty of Vertex Form: The beauty of this form lies in its simplicity. The vertex, that crucial turning point, is right there in the equation! The h value represents the x-coordinate of the vertex, and the k value represents the y-coordinate. This form immediately gives you a visual sense of where the parabola sits on the coordinate plane. For instance, if we have f(x) = 2(x - 1)^2 + 3, we instantly know the vertex is at (1, 3).

Why is the Vertex Form so Important?: Vertex form isn't just a neat trick; it's a fundamental tool for analyzing and understanding quadratic functions. It allows us to quickly identify key features of the parabola, such as its vertex, axis of symmetry, and direction of opening. These features are essential for graphing the parabola accurately and solving related problems. Understanding vertex form also provides a solid foundation for tackling more advanced concepts in algebra and calculus.

Connecting the Dots: Now, let's connect the dots. We know our parabola has a minimum at (-3, 9). This means (-3, 9) is our vertex, so h = -3 and k = 9. Plugging these values into the vertex form gives us:

f(x)=a(xβˆ’(βˆ’3))2+9f(x) = a(x - (-3))^2 + 9

f(x)=a(x+3)2+9f(x) = a(x + 3)^2 + 9

See how we're getting closer to the answer? We've narrowed it down to equations that have the form a(x + 3)^2 + 9. Now, we need to figure out what the a value should be. Remember, a tells us whether the parabola opens upwards or downwards. Since we have a minimum point, the parabola must open upwards. This means a must be positive. This key piece of information will help us eliminate some answer choices.

Analyzing the Answer Choices: Finding the Perfect Fit

Alright, let's roll up our sleeves and dissect those answer choices. We've got our vertex form equation skeleton: g(x) = a(x + 3)^2 + 9. Now, we need to find the equation that fits this form and has a positive 'a' value. Let's take a look at our options:

A. g(x)=3(xβˆ’3)2+9g(x) = 3(x - 3)^2 + 9 B. g(x)=2(x+3)2+9g(x) = 2(x + 3)^2 + 9 C. g(x)=βˆ’(x+3)2+9g(x) = -(x + 3)^2 + 9 D. g(x) = - rac{1}{2}(x - 3)^2 + 9

Breaking Down Each Option

  • Option A: g(x)=3(xβˆ’3)2+9g(x) = 3(x - 3)^2 + 9: Notice the (x - 3)^2 part? This tells us the vertex would be at (3, 9), but we need it at (-3, 9). So, this one's out.
  • Option B: g(x)=2(x+3)2+9g(x) = 2(x + 3)^2 + 9: Bingo! This one looks promising. We have (x + 3)^2, which means the x-coordinate of the vertex is -3, and the + 9 gives us the y-coordinate of 9. Plus, the 'a' value is 2, which is positive, meaning the parabola opens upwards. This is a strong contender.
  • Option C: g(x)=βˆ’(x+3)2+9g(x) = -(x + 3)^2 + 9: This one has (x + 3)^2 and + 9, so the vertex is in the right place. However, the 'a' value is -1 (negative). This means the parabola opens downwards, which would give us a maximum point, not a minimum. So, this option is incorrect.
  • Option D: g(x) = - rac{1}{2}(x - 3)^2 + 9: Here, we have (x - 3)^2, placing the x-coordinate of the vertex at 3, not -3. Also, the 'a' value is negative, meaning the parabola opens downwards. This option doesn't fit the bill.

The Winner!

After carefully analyzing each option, it's clear that Option B, g(x)=2(x+3)2+9g(x) = 2(x + 3)^2 + 9, is the correct answer. It matches the vertex form with the correct vertex (-3, 9) and has a positive 'a' value, ensuring the parabola opens upwards, giving us a minimum point.

Key Takeaways: Mastering Parabola Equations

Alright, mathletes, we've successfully navigated this parabola puzzle! Let's recap the key takeaways so you can confidently tackle similar problems in the future:

  1. Vertex Form is Your Friend: The vertex form, f(x)=a(xβˆ’h)2+kf(x) = a(x - h)^2 + k, is the secret weapon for understanding parabolas. It directly reveals the vertex (h, k) and the direction of opening (based on the sign of 'a').
  2. Minimum vs. Maximum: A positive 'a' value means the parabola opens upwards, resulting in a minimum point. A negative 'a' value means it opens downwards, resulting in a maximum point.
  3. Careful with Signs: Pay close attention to the signs in the equation, especially when dealing with (x - h) and (x + h). A (x + 3) term means h = -3, and a (x - 3) term means h = 3.
  4. Eliminate Strategically: When faced with multiple-choice questions, use the information you know to eliminate incorrect options. This will narrow down your choices and increase your chances of selecting the right answer.

By understanding these key concepts, you'll be well-equipped to tackle a wide range of parabola problems. So, keep practicing, keep exploring, and remember that every math puzzle is just a step closer to mastering the beautiful world of mathematics!

Practice Makes Perfect: Test Your Parabola Prowess

Now that we've cracked this problem, it's time to put your newfound knowledge to the test! Let's try a couple of similar practice questions to solidify your understanding of parabolas and their equations. Remember, practice is the key to mastering any math concept, and parabolas are no exception.

Practice Question 1:

The graph of a function is a parabola with a maximum point at (2, 5). Which of the following equations could represent the function?

A. f(x)=(xβˆ’2)2+5f(x) = (x - 2)^2 + 5 B. f(x)=βˆ’2(x+2)2+5f(x) = -2(x + 2)^2 + 5 C. f(x)=βˆ’(xβˆ’2)2+5f(x) = -(x - 2)^2 + 5 D. f(x)=3(x+2)2+5f(x) = 3(x + 2)^2 + 5

Hint: Remember, a maximum point means the parabola opens downwards. What does that tell you about the 'a' value?

Practice Question 2:

A parabola has a minimum point at (-1, -3). Which equation could represent this function?

A. g(x)=βˆ’(x+1)2βˆ’3g(x) = -(x + 1)^2 - 3 B. g(x)=2(xβˆ’1)2βˆ’3g(x) = 2(x - 1)^2 - 3 C. g(x)=(x+1)2+3g(x) = (x + 1)^2 + 3 D. g(x)=(x+1)2βˆ’3g(x) = (x + 1)^2 - 3

Hint: Focus on the vertex form and the sign of the 'a' value. Think about which options match the given vertex and direction of opening.

Solutions and Explanations

We'll reveal the solutions and explanations in the next section, but try to solve these problems on your own first. Don't be afraid to make mistakes – that's how we learn! Work through each option, apply the concepts we discussed, and see if you can pinpoint the correct answer.

By tackling these practice questions, you'll not only reinforce your understanding of parabola equations but also develop your problem-solving skills. So, grab a pencil, put on your thinking cap, and let's conquer these parabolas!

Solutions and Explanations: Checking Your Answers

Alright, math whizzes, let's dive into the solutions and explanations for our practice questions. This is where we solidify our understanding and iron out any remaining kinks in our parabola knowledge. So, let's see how you did!

Practice Question 1: Solution and Explanation

The correct answer is C. f(x)=βˆ’(xβˆ’2)2+5f(x) = -(x - 2)^2 + 5.

Here's why:

  • We're given a maximum point at (2, 5), which means the vertex is (2, 5). This tells us that h = 2 and k = 5 in the vertex form equation.
  • Since it's a maximum point, the parabola opens downwards, meaning the 'a' value must be negative.
  • Now, let's analyze the options:
    • A. f(x)=(xβˆ’2)2+5f(x) = (x - 2)^2 + 5: Has the correct vertex, but 'a' is positive, so it opens upwards (incorrect).
    • B. f(x)=βˆ’2(x+2)2+5f(x) = -2(x + 2)^2 + 5: Has a negative 'a' (good!), but the vertex is at (-2, 5) (incorrect).
    • C. f(x)=βˆ’(xβˆ’2)2+5f(x) = -(x - 2)^2 + 5: Correct vertex (2, 5) and a negative 'a' value (opens downwards) – correct!
    • D. f(x)=3(x+2)2+5f(x) = 3(x + 2)^2 + 5: Positive 'a' (opens upwards) and incorrect vertex (-2, 5) (incorrect).

Practice Question 2: Solution and Explanation

The correct answer is D. g(x)=(x+1)2βˆ’3g(x) = (x + 1)^2 - 3.

Here's the breakdown:

  • We have a minimum point at (-1, -3), so the vertex is (-1, -3). This means h = -1 and k = -3.
  • A minimum point indicates the parabola opens upwards, so the 'a' value must be positive.
  • Let's examine the options:
    • A. g(x)=βˆ’(x+1)2βˆ’3g(x) = -(x + 1)^2 - 3: Negative 'a' value (opens downwards) – incorrect.
    • B. g(x)=2(xβˆ’1)2βˆ’3g(x) = 2(x - 1)^2 - 3: Incorrect vertex (1, -3) – incorrect.
    • C. g(x)=(x+1)2+3g(x) = (x + 1)^2 + 3: Correct x-coordinate for the vertex, but incorrect y-coordinate (should be -3) – incorrect.
    • D. g(x)=(x+1)2βˆ’3g(x) = (x + 1)^2 - 3: Correct vertex (-1, -3) and positive 'a' value (opens upwards) – correct!

Key Insights

  • Vertex, Vertex, Vertex: Always start by identifying the vertex and ensuring the equation matches it.
  • Sign of 'a': The sign of 'a' is your compass – it tells you whether the parabola opens upwards (positive) or downwards (negative).
  • Don't Overlook Details: Pay close attention to every detail, especially the signs and numbers within the equation.

By working through these solutions and explanations, you've not only checked your answers but also reinforced your understanding of the underlying principles. Keep practicing, and you'll become a parabola pro in no time!

Beyond the Basics: Exploring More Parabola Puzzles

So, you've mastered the basics of identifying parabola equations from their vertex and direction of opening. That's fantastic! But the world of parabolas is vast and fascinating, with many more interesting puzzles to explore. Let's take a peek beyond the basics and see what other challenges await us in the realm of quadratic functions.

1. Converting Between Forms: We've been working with the vertex form, which is great for identifying the vertex. But parabolas can also be represented in standard form: f(x)=ax2+bx+cf(x) = ax^2 + bx + c. Can you convert between these forms? This involves completing the square, a powerful technique that allows you to rewrite a quadratic expression in vertex form.

2. Finding the Equation from Three Points: What if you're not given the vertex, but instead three points that lie on the parabola? Can you find the equation? This requires setting up a system of equations and solving for the coefficients a, b, and c in the standard form. It's like being a parabola detective, piecing together clues to uncover the equation!

3. Applications of Parabolas: Parabolas aren't just abstract mathematical curves; they appear in the real world in many ways! Think about the trajectory of a ball thrown in the air, the shape of a satellite dish, or the cross-section of a suspension bridge cable. Can you use your knowledge of parabolas to model and solve problems related to these real-world scenarios?

4. Parabolas and the Quadratic Formula: The quadratic formula is a powerful tool for finding the roots (x-intercepts) of a quadratic equation. How do the roots relate to the parabola's graph? Can you use the discriminant (the part under the square root in the quadratic formula) to determine the number of roots and the nature of the parabola's intersection with the x-axis?

5. Transformations of Parabolas: Just like other functions, parabolas can be transformed by shifting, stretching, and reflecting them. Can you identify the transformations that have been applied to a parabola given its equation? How do these transformations affect the vertex and other key features of the graph?

By exploring these more advanced topics, you'll deepen your understanding of parabolas and their role in mathematics and the world around us. So, keep your curiosity burning, and continue your journey into the captivating world of quadratic functions!

Final Thoughts: Embracing the Parabola Power

Guys, we've journeyed through the fascinating world of parabolas, from understanding the vertex form to tackling practice problems and even glimpsing beyond the basics. We've uncovered the secrets of identifying parabola equations, and hopefully, you're feeling much more confident in your ability to handle these curvy conundrums.

Remember, mathematics is like a grand adventure, full of challenges and discoveries. Parabolas are just one piece of this beautiful puzzle, and by mastering them, you're unlocking a powerful tool for problem-solving and critical thinking.

So, embrace the parabola power! Keep practicing, keep exploring, and never stop asking questions. The more you delve into the world of math, the more you'll appreciate its elegance, its logic, and its incredible ability to describe the world around us.

And who knows, maybe one day you'll be the one to unravel a new mathematical mystery, inspired by the simple yet profound beauty of the parabola. Keep learning and keep shining!